Replace String with space in Xsl/Xslt

Replace Method for Replace contents,

<xsl:template name="replaceCharsInString">
<xsl:param name="stringIn"/>
<xsl:param name="charsIn"/>
<xsl:param name="charsOut"/>
<xsl:choose>
<xsl:when test="contains($stringIn,$charsIn)">
<xsl:value-of select="concat(substring-before($stringIn,$charsIn),$charsOut)"/>
<xsl:call-template name="replaceCharsInString">
<xsl:with-param name="stringIn" select="substring-after($stringIn,$charsIn)"/>
<xsl:with-param name="charsIn" select="$charsIn"/>
<xsl:with-param name="charsOut" select="$charsOut"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$stringIn"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>


Below code for call the replace method and provided by three parameters
1. Full String
2. Replace text (charIn)
3 Replace from (charOut)
In my example i have used amp; i.e. & to replace with '' i.e. space for your reference code is here.

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<xsl:variable name="myString" select="page/meta/sharefeed"/>
<xsl:variable name="myNewString">
<xsl:call-template name="replaceCharsInString">
<xsl:with-param name="stringIn" select="string($myString)"/>
<xsl:with-param name="charsIn" select="'amp;'"/>
<xsl:with-param name="charsOut" select="''"/>
</xsl:call-template>
</xsl:variable>
<xsl:variable name="myNewRealString" select="string($myNewString)"/>